add another part of the circle. now 1/4 circle done

This commit is contained in:
hugova 2025-06-29 02:04:08 +02:00
parent c2a5af481f
commit 380728a80a
3 changed files with 60 additions and 1 deletions

View file

@ -7,3 +7,7 @@
t2 = $E1
X_rel = radius
Y_rel = $E3
temp = $E4
temp_ = $E7
btp_mem_pos_center = $E5 ;; 16bit <fix>
btp_mem_pos_inv = $EE ;; 16bit <fix>

View file

@ -19,16 +19,71 @@
LSR
STA t1
draw_center_px_in_circle:
JSR pixel_draw
LDA btp_mem_pos
STA btp_mem_pos_center
LDA btp_mem_pos + 1
STA btp_mem_pos_center + 1
;; btp_mem_pos_center_two = 2*btp_mem_pos_center | used later for calculating btp_mem_pos_inv
btp_mem_pos_center_two = btp_mem_pos_center
Mult_16 btp_mem_pos_center, btp_mem_pos_center + 1
draw_right_px_in_circle:
CLC
LDA X_pos
ADC radius
STA X_pos
;; We only draw the first pixel using absolute position.
;; After that we use relative position.
JSR pixel_draw
;; This sets byte_to_paint, btp_mem_pos and Y
while_x_bigger_then_y:
;STY temp
;LDY #$00
draw_pixel:
LDA byte_to_paint ;A byte containing a single 1. Coresponds to X position in the chunk.
ORA (btp_mem_pos), Y
STA (btp_mem_pos), Y
draw_pixel_inv:
SEC
LDA btp_mem_pos_center_two
SBC btp_mem_pos
STA btp_mem_pos_inv
LDA btp_mem_pos_center_two + 1
SBC btp_mem_pos + 1
STA btp_mem_pos_inv + 1
;; calculate the inverted y value Y = 7-Y
STY temp
LDA #$07
SEC
SBC temp
TAY
;; calculate byte_to_paint_inv (could be faster with lookup table)
LDA byte_to_paint
STA temp_
LDA #%10000000
jmp start_calc
calc:
LSR A
start_calc:
LSR temp_
BCC calc
; A = byte_to_paint_inv
ORA (btp_mem_pos_inv), Y
STA (btp_mem_pos_inv), Y
;;Recover the Y value (we changed it because evrything is inverted)
ldy temp
increment_y_pos:
INC Y_rel ; y++
INY

View file

@ -3,7 +3,7 @@
LDA #$50
STA X_pos
STA Y_pos
LDA #$55
LDA #$35
STA radius
JSR circle
.endscope