reduse instructions in circle draw
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7cd03c02ba
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5e3eb78506
2 changed files with 9 additions and 10 deletions
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@ -35,4 +35,5 @@
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Y_qda = $DE
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Y_qdb = $DF
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Y_qbb = $CE
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temp__ = $CD
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Y_qaa = Y_copy
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@ -76,7 +76,7 @@ draw_upper_px_in_circle:
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draw_left_px_in_circle: ;similar as above
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SEC
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LDA X_pos
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STA temp_
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STA temp__
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SBC radius
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STA X_pos
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@ -91,13 +91,11 @@ draw_left_px_in_circle: ;similar as above
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LDA byte_to_paint
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STA byte_to_paint_qca
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LDA temp_
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LDA temp__
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STA X_pos
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draw_lower_px_in_circle: ;similar as above
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CLC
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LDA Y_pos
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STA temp_
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ADC radius
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STA Y_pos
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@ -120,7 +118,7 @@ draw_lower_px_in_circle: ;similar as above
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LDA temp_
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STA Y_pos
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draw_right_px_in_circle:; similar as above
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CLC
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;; C =0 becuse pixel_draw
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LDA X_pos
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ADC radius
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STA X_pos
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@ -137,7 +135,7 @@ draw_right_px_in_circle:; similar as above
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LDX #$08 ; X=8 always expected inside the loop
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while_x_bigger_then_y:
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draw_pixels.
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draw_pixels:
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draw_qaa:
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LDY Y_qaa
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LDA byte_to_paint ;A byte containing a single 1. Coresponds to 2^rest(X_pos/8)
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@ -179,18 +177,19 @@ draw_qab:
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;; Y_rel and X_rel is the X and Y in the eye of the algorithm. Thsese are calculated seperatly from the pixel cordinates,
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;; but are modified at the same time. This is becsuse the pixel cordinate system is complex (see pixel draw)
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LDY #$07 ;; Y is expected to be 7 from this point on in the loop
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change_Y:
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INC Y_rel ; y++
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qaa_y:
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DEC Y_qaa
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BPL qaa_y_end
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qaa_y_underflow:
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LDA #$07
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STA Y_qaa
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;; Switch to chunk bellow
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; So we subtract #$0140
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Sub_16 btp_mem_pos, btp_mem_pos + 1, #$40, #$01 ;-320
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Sub_16 btp_mem_pos_qba, btp_mem_pos_qba + 1, #$40, #$01,!
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STY Y_qaa ; Y_qaa =$07
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qaa_y_end:
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qda_y:
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INC Y_qda
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@ -263,8 +262,7 @@ qdb_y:
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qdb_overflow:
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Sub_16 btp_mem_pos_qdb, btp_mem_pos_qdb + 1, #$3f, #$01, ! ;+320
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Sub_16 btp_mem_pos_qcb, btp_mem_pos_qcb + 1, #$40, #$01, ! ;+320
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LDA #$07
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STA Y_qdb
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STY Y_qdb
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qdb_y_end:
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qbb_y:
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